Radiant Oscillator Circuit / Don Smith Part 6: COP = 50? read description
imageshack.us Like don smith said, 2 times the volts in a resonant system, is now 4 times the output Joules= .5 X Cap in uF X Volts(2) X Freq(2) so .5 = formula constant C (capacitance in all wires and coils say 100pF, = .000.000.000100uf (which is 1E-9) (cause prob easily more 🙂 XV(2) XF(2) V= 2000V (conservatively, shocks me thru the tesl wires) F = 3.22khz (2000 x 2000) = 4000000 X (3220 X 3220) = 10368400 so 4000000 x 10368400 x .000000000100 uf x .5 = 2073.68 Joules (that’s just a guess, but say there was even 1nF, that would be over 20 KiloJoules in the system if so!!!!! If 12 volts DC meets 12 Watts of lights, and a neg connection, it SHOULD demand 1 AMP to run them…. AM I RIGHT?? so Required = 12 v X 1 A = 12 watts (here only 24v X .5A required for 12 watts DC) **Actual system use, 24v X .01A = 0.24 Watts lighting 12 watts over their full brightness 🙂 =12 / 0.24 =COP 50 (5000% efficient) Here is now reading only slightly noticeable current, AND the lights are now above their full brightness, but not advisable unless you series all the lights or use better coils (24volt) Also the ignition coils are being driven past their rated 12v for L1 voltage, so clearly 24v is pushing it to its limit.