freewheeling magnifier test 2 .wmv

Hi all thanks for your comments on the previous video. I made a mistake on the calculation.and this mistake pushed me to further thinking on the subject And as Stephan (hartiberlin ) asked me i redo the test with the same cap value. And what puzzled me, is that by a direct transfer of energy from one cap to the other, If i apply the energy formula ( 1/2 C*U ^2), i loose half the energy from the initial input. I mean there is no (or almost no) resistance in the circuit and the energy desapear ??? Where is this energy gone ? Than i redo the experiment with the discharging of the main cap through the diode and inductor. An this time i have really a resistance due to the diode and the inductor (107 ohms). But at the end the voltage is about the same. I mean that if i add the remaining voltage in the main cap (about 1.9 volt) and in the filled cap (about 8.4 volts), which gives a created potential difference of 6.5 volts by the use of only 5 volts of initial potential difference. All this let me think that in this kind of energy transfer. by using an inductor and a diode , we can increase the efficiency of the sayd transfer . And the question is How and Why this is possible ? good luck at all Laurent this subject is discussed at OU in the thread (electrical igniter)

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